python - Remove a nested list if any of multiple values is found -

i have list of lists , i'd remove nested lists contain of multiple values.

list_of_lists = [[1,2], [3,4], [5,6]] indices = [i i,val in enumerate(list_of_lists) if (1,6) in val]  print(indices) [0] 

i'd lists of indices conditions can:

del list_of_lists[indices] 

to remove nested lists contain values. i'm guessing problem try check against multiple values (1,6) using either 1 or 6 works.

you use set operation:

if not {1, 6}.isdisjoint(val) 

a set disjoint if none of values appear in other sequence or set:

>>> {1, 6}.isdisjoint([1, 2]) false >>> {1, 6}.isdisjoint([3, 4]) true 

or test both values:

if 1 in val or 6 in val 

i'd not build list of indices. rebuild list , filter out don't want in new list:

list_of_lists[:] = [val val in list_of_lists if {1, 6}.isdisjoint(val)] 

by assigning [:] whole slice replace indices in list_of_lists, updating list object in-place:

>>> list_of_lists = [[1, 2], [3, 4], [5, 6]] >>> another_ref = list_of_lists >>> list_of_lists[:] = [val val in list_of_lists if {1, 6}.isdisjoint(val)] >>> list_of_lists [[3, 4]] >>> another_ref [[3, 4]] 

see what difference between slice assignment slices whole list , direct assignment? more detail on assigning slice does.