Regex to match a string not followed by some string -

i have string block below

1. while #enginespeed$b4tgup# 2. while #acceleratorpedal$desddd# <=2 3. while #acceleratorpeda@$desddd# <=2 4. while #acceleratorpe#al$desddd# <=2 5. while #acceleratorp@dal$desddd# <=2 6. while #acceleratorpeda l$desddd# <=2 7. 设置 #acceleratorpedal$y6qs8m#=@acceleratorpedal+0.06 8. 设置 #waitstart$jhx0vu#=11 9. 设置 #waitstart$jhx0vu#^11 10. 设置 #waitstart$jhx0vu#_11 11. 设置 #waitstart$jhx0vu#-11 12. 设置 #acceleratorquora$yd6ba3#=1 13. 设置 #acceleratorquora$yd6bd3#=1 14. 15. check #enginepower# 16. while #enginespeed 17. set #waitstart 18. set #waitstart<13 19. set #waitstart<=13 20. set #waitstart <= 13 

now want have regex match substring starts # not followed # or not followed substring $\w{6}#.

so in string block above line 16,17,18,19,20 match,in line 16 result #enginespeed,in line 17 result #waitstart,the others not match, in line 20 ,the result #waitstart, followed <= 13,not followed # or $\w{6}#,so it's match!

for example,in line 15 string check #enginepower#,it starts #,but followed #,in line 13 string 设置 #acceleratorquora$yd6bd3#=1,it starts #,but followed substring $\w{6}#.

i have wrote regex #\w+(?<!#|$\w{6}#),but test result in regexbuddy shown in picture below,almost every line match,it doesn't meet requirement,how can can modify regex? in advance!

from strings above want match

16. while #enginespeed
17. set #waitstart
18. set #waitstart<13
19. set #waitstart<=13
20. set #waitstart <= 13

you can use

(?<=\s)#\w+(?!.*[@$#]) 

see this regex demo

details:

• (?<=\s) - there must whitespace before...
• # - literal hash
• \w+ - 1 or more word chars
• (?!.*[@$#]) - fail match if there @, or $, or # somewhere after \w+ on line.