c++ - Shifting array elements by n positions -

i have basic knowledge in c, c++ , im trying insert n elements @ k positions in array , shift k+1 element in array. have used 2 loops this

void insert(int n,int k) {   int temp=arraya[k][4];    for(int u=k+1;u<=rowa;u++)   {     arraya[k+n][4]=arraya[k+1][4];     arraya[k+n][3]=bigradius;     arraya[k+n][2]=arraya[k+1][2];     arraya[k+n][1]=arraya[k+1][1];     arraya[k+n][0]=arraya[k+1][0];   }    for(int pos=k;pos<=k+n-1;pos++,)   {        arraya[pos][4]=temp;     arraya[pos][3]=b     arraya[pos][2]=s1;     arraya[pos][1]=s2;     arraya[pos][0]=s3;     }   } 

where n no of new elements,k position new elements inserted,s1,s2,s3..are values

if initial file 0.74172455 0.03613250 0.82822931 0.03121938 0 0.45620244 0.33476580 0.92169053 0.03121938 1 0.13701758 0.74540644 0.56569663 0.03121938 2 0.94162524 0.13094005 0.62107182 0.03121938 3

but in output if im inserting 3 elements in position 0,then elements @ position 1,2 missing

-0.0104065  0.0312194 0.0728452 0.0104065      0   0.0104065 -0.0312194 0.0520323 0.0104065      0   0.0104065 -0.0312194 0.0520323 0.0312194      0   0.941625   0.13094   0.621072  0.0312194      3  

to insert n elements @ index k of array, try logic:

initialize original array having elements. now, take values of n, k in variables , n elements insert in array (let's to_add[]) user. now, initialize second array of length = length of main array + n.
(1) having required values , arrays initialized, run loop index = 0 index = k-1 of main array , copy elements the second array.
(2) now, run second loop index = k index = k + n - 1 second array , copy elements index = index - k of to_add array second array.
(3) lastly, run third loop index = k + n index = (length of second array) - 1 of second array , copy elements index = index - n of main array second array.

here's c++ code above logic.

int k,n; int main_array[x] = { /* elements of original array */ }; /* display main array */ cout << "enter index position @ enter elements \n" ; cin >> k; cout << "\n how many elements want enter? \n" ; cin >> n; int to_add[n]; int final_array[x+n]; /* accept elements added to_add array */  //first loop for(int = 0; < k; i++){     final_array[i] = main_array[i]; }  //second loop for(int = k; < k+n; i++){     final_array[i] = to_add[i-k]; }  //last loop for(int = k+n; < x+n; i++){     final_array[i] = main_array[i-n]; }  /* display final_array */ 

i hope understand , solves problem.