Transfer C# array to PHP to show in browser -

hy everyone, have problem can't solve. i've searched answers haven't find usefull answer. have c# code insert mysql database values, want retrieve select. array want display web browser through php because need things array. c# code use transfer array php:

        while (reader.read())             {                 int numbers = 0;                 if (!reader.isdbnull(reader.getordinal("numbers")))                 {                     numbers= reader.getint16("numbers");                 }                 num n = new num(numbers);                 list.add(n);             }         var result = string.join(",", list);          string urladdress = "http://localhost/number.php";         using (webclient client = new webclient())         {             namevaluecollection postdata = new namevaluecollection()             {                 { "result", result}             };             string pagesource = encoding.utf8.getstring(client.uploadvalues(urladdress, postdata));         } 

and in php use:

      <?php       $result = $_post["result"];       echo $result;       ?> 

but doesn't return in web browser. need help.

edit: php code. wanted don't use select in php, want c# code.

    <?php     $mysql_hostname = "localhost";     $mysql_user = "root";     $mysql_password = "";     $mysql_database = "alex";     $prefix = "";     $bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("could not connect database");     mysql_select_db($mysql_database, $bd) or die("could not select database");     ?>      numbers:     <form method="get" action="number.php">     <?php          $query = mysql_query("select * enumerating");          while ($row = mysql_fetch_assoc($query)) { ?>             <label><?php echo $row['numere']; ?></label><input type="checkbox" value="<?php echo $row['numere']; ?>" name="numar[]"><br>      <?php }      ?>             <input type="submit" name="send" value="salveaza">      </form>      <?php     if(isset($_get['send']))     {     ($i=0;$i<count($_get['number']);$i++)        {             mysql_query("insert enumerating2(numbers) values('".$_get['number'][$i]."');");        }    echo "<pre>successfully!<pre>";    }           ?>