google spreadsheet - Get column headers with query language -

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i'm using query language query data spreadsheet. retrieve first row(column headers), how do that?

currently i'm using: select * ( = -1 ) , data in column never equal -1, returns column headers.

is there straightforward way this?

you can use query(a:z, "select * limit 0", 1) meaning: select all, return @ 0 rows. result header row returned (the 3rd parameter make clear there 1 header row).

but it's not natural use query purpose. function array_constrain provided purpose of truncating array of data. example,

=array_constrain(a:z, 1, 1e7)

returns first row of given array. (since no limit on number of columns needed, gave 1e7 = 10,000,000 maximal number of columns. spreadsheet can't have many cells.)


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