is there a more efficient way to filter regex match string? -

is there a more efficient way to filter regex match string? -

- April 15, 2012

var s = '/home/src/_layouts/default.pug';// wanna '_layouts/default' var regex = /(src\/.*)/; var m = s.match(regex); var t = m[0].match(/([^(src\/)].*)(?=\..*$)/)[0]; console.log(t);// outputs "_layouts/default"

it works no elegant enough, wanna more efficient, can me? thanks.

the regex you're after /src\/([^.]*)\..+/.

it'll match src, capture before dot. [^.] negated character class ("match except these characters"), meaning it'll filename , not extension.

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