xml - XSLT: Group different element types -

my source xml looks follows:

<a>   <item>     <x>10</x>     <y>20</y>     <data1>foo</data1>   </item> </a> <b>   <item>     <x>10</x>     <y>20</y>     <data2>bar</data2>   </item> </b> <a>   <item>     <x>11</x>     <y>20</y>     <data1>foo2</data1>   </item> </a> <b>   <item>     <x>11</x>     <y>20</y>     <data2>bar2</data2>   </item> </b> 

note as , bs occur pairwise respect values of x , y. note there other elements containing nested item element should ignored. now, goal group elements having same values x , y new elements looking this:

<newelement>     <x>10</x>     <y>20</y>     <data1>foo</data1>     <data2>bar</data2> </newelement> <newelement>     <x>11</x>     <y>20</y>     <data1>foo2</data1>     <data2>bar2</data2> </newelement> 

i have read muenchian grouping, seems works same elements (e.g., in example group as having same values xand y). how can group different elements?

the following stylesheet:

xslt 1.0

<xsl:stylesheet version="1.0"  xmlns:xsl="http://www.w3.org/1999/xsl/transform"> <xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>  <xsl:key name="b" match="b/item" use="concat(x, '|', y)" />  <xsl:template match="/root">     <root>         <xsl:for-each select="a/item">             <newelement>                 <xsl:copy-of select="*"/>                 <xsl:copy-of select="key('b', concat(x, '|', y))/data2"/>             </newelement>         </xsl:for-each>     </root> </xsl:template>  </xsl:stylesheet> 

applied input example (after adding root element make well-formed!), produces:

<?xml version="1.0" encoding="utf-8"?> <root>    <newelement>       <x>10</x>       <y>20</y>       <data1>foo</data1>       <data2>bar</data2>    </newelement>    <newelement>       <x>11</x>       <y>20</y>       <data1>foo2</data1>       <data2>bar2</data2>    </newelement> </root>